A partially ordered set (also called a poset) is a pair $\langle P, \leq \rangle$ of a set $P$ and a binary relation $\leq$ on $P$ such that for all $p,q,r \in P$, the following properties are satisfied:

• Reflexivity: $p \leq p$
• Transitivity: $p \leq q$ and $q \leq r$ implies $p \leq r$
• Anti-symmetry: $p \leq q$ and $q \leq p$ implies $p = q$

$P$ is referred to as the poset’s underlying set and $\leq$ is referred to as its order relation.

Notations and fundamentals

Greater than

A greater than relation $\geq$ can be derived as the transpose of a poset’s less than relation: $a \geq b$ means that $b \leq a$.

Incomparability

For poset elements $p$ and $q$, if neither $p \leq q$ nor $q \leq p$ then we say that $p$ and $q$ are incomparable, and write $p \parallel q$.

Strict orders

From any poset $\langle P, \leq \rangle$, we can derive an underlying strict order $<$. For $p, q \in P$, $p < q$ means that the following conditions are satisfied:

• 1.) $p \leq q$
• 2.) $p \neq q$

The cover relation

From any poset $\langle P, \leq \rangle$, we can derive an underlying cover relation $\prec$, defined such that for $p,q \in P$, $p \prec q$ whenever the following two conditions are satisfied:

• 1.) $p < q$
• 2.) For all $r \in P$, $p \leq r < q$ implies $p = r$

$p \prec q$ is pronounced “$p$ is covered by $q$”, or “$q$ covers $p$”, and $q$ is said to be a cover of $p$.

Hasse diagrams

Let $\langle P, \leq \rangle$ be the poset such that $P = \{ p, q, r \}$ and $\leq = \{(p,p),(p,q)(p,r),(q,q),(q,r),(r,r) \}$. The order relation $\leq$, being binary, can be depicted as a directed graph, though the resulting image leaves something to be desired.

Including an edge for every pair in $\leq$ results in a rather noisy looking graph. In particular, as long as we are under assumption that the graph we are viewing depicts a poset, placing a reflexive edge on each node is tedious and redundant. Our first step toward cleaning up this graph is to remove all reflexive edges, instead leaving reflexivity as an implicit assumption. Likewise, we can leave those edges which are implied by transitivity — $(p,r)$ is the only such edge in this poset — implicit. As a final step, we remove the arrow heads from our edges, leaving their directions implied by the y-coordinates of the nodes they connect: an edge between two nodes means that the poset element corresponding to the lower node is less than the poset element corresponding to the higher node. The simplified depiction of $\langle P, \leq \rangle$ then follows.

Such a depiction is called a Hasse diagram; drawing a Hasse diagram is the standard method for visually depicting a poset. Now that we understand what Hasse diagrams are, we can provide a concise definition: a Hasse diagram is a graph-based visual depiction of a poset $\langle P, \leq \rangle$, where elements of $P$ are represented as nodes, and for all $(p,q) \in P^2$ such that $p \prec q$, an upward edge is drawn from $p$ to $q$.

$p \leq q$ requires that $p$ must appear lower in a Hasse diagram than $q$. However, the converse is not true. In the following Hasse diagram, $t \parallel r$ even though $t$ is positioned lower than $r$.

Duality

Every poset $\langle P, \leq \rangle$ has a corresponding dual poset $\langle P^{\partial}, \geq \rangle$, where $P^{\partial}$ (pronounced “P op”) is a set whose elements are in correspondence with those of $P$, and $\geq$ is the transpose of $\leq$ discussed previously. The Hasse diagram of $P^{\partial}$ is obtained by flipping the Hasse diagram of $P$ upside down. Whenever $\phi$ is a propsition about posets, we obtain $\phi$’s dual proposition $\phi^{\partial}$ by replacing all occurrences of $\leq$ with $\geq$ and all occurrences of $\geq$ with $\leq$.

The existence of dual posets and dual propositions gives rise to the duality principle: if a proposition $\forall P. \phi$, quantified over all posets, is true then its dual $\forall P. \phi^{\partial}$ is also true. The duality principle works because instantiating $\forall P. \phi$ with a poset $P$ is equivalent to instantiating $\forall P. \phi^{\partial}$ with $P^{\partial}$. This is due to the fact that $a \leq b$ in $P$ iff $a \geq b$ in $P^{\partial}$. Theorems involving posets often come with a free dual theorem thanks to the duality principle.

Additional Material

For some additional examples of posets, see examples. To test your knowledge of posets, try these exercises. The most useful operators on elements of a poset are called the join and meet. We can relate the elements of one poset to another through the use of monotone functions.